6x+3=2x^2

Solution for 6x+3=2x^2 equation:

6x+3=2x^2

We move all terms to the left:

6x+3-(2x^2)=0

determiningTheFunctionDomain
-2x^2+6x+3=0

a = -2; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·(-2)·3
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{15}}{2*-2}=\frac{-6-2\sqrt{15}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{15}}{2*-2}=\frac{-6+2\sqrt{15}}{-4}
$